10.4: Lewis Structures of Molecular Compounds (2024)

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    Learning Objectives
    • Draw Lewis structures depicting the bonding in simple molecules

    Thus far, we have discussed the Lewis structure of atoms and ionic compounds. We also use Lewis symbols to indicate the formation of covalent bonds, which are shown in Lewis structures, drawings that describe the bonding in molecules and polyatomic ions. For example, when two chlorine atoms form a chlorine molecule, they share one pair of electrons:

    10.4: Lewis Structures of Molecular Compounds (1)

    The Lewis structure indicates that each Cl atom has three pairs of electrons that are not used in bonding (called lone pairs) and one shared pair of electrons (written between the atoms). A dash (or line) is usually used to indicate a shared pair of electrons:

    10.4: Lewis Structures of Molecular Compounds (2)

    In the Lewis model, a single shared pair of electrons is a single bond. Each Cl atom interacts with eight valence electrons total: the six in the lone pairs and the two in the single bond.

    Lewis Structure of Molecules: https://youtu.be/xWiFCqA9Ur0

    Writing Lewis Structures with the Octet Rule

    For very simple molecules and molecular ions, we can write the Lewis structures by merely pairing up the unpaired electrons on the constituent atoms. See these examples:

    10.4: Lewis Structures of Molecular Compounds (3)

    For more complicated molecules and molecular ions, it is helpful to follow the step-by-step procedure outlined here:

    1. Determine the total number of valence (outer shell) electrons among all the atoms. For cations, subtract one electron for each positive charge. For anions, add one electron for each negative charge.
    2. Draw a skeleton structure of the molecule or ion, arranging the atoms around a central atom. (Generally, the least electronegative element should be placed in the center.) Connect each atom to the central atom with a single bond (one electron pair).
    3. Distribute the remaining electrons as lone pairs on the terminal atoms (except hydrogen), completing an octet around each atom.
    4. Place all remaining electrons on the central atom.
    5. Rearrange the electrons of the outer atoms to make multiple bonds with the central atom in order to obtain octets wherever possible.

    Let us determine the Lewis structures of SiH4, \(\ce{CHO2-}\), NO+, and OF2 as examples in following this procedure:

    1. Determine the total number of valence (outer shell) electrons in the molecule or ion.
      • For a molecule, we add the number of valence electrons on each atom in the molecule:

        \(\begin{align} &\phantom{+}\ce{SiH4}\\ &\phantom{+}\textrm{Si: 4 valence electrons/atom × 1 atom = 4}\\ &\underline{\textrm{+H: 1 valence electron/atom × 4 atoms = 4}}\\ &\hspace{271px}\textrm{= 8 valence electrons} \end{align}\)

      • For a negative ion, such as \(\ce{CHO2-}\), we add the number of valence electrons on the atoms to the number of negative charges on the ion (one electron is gained for each single negative charge):

        \(\ce{CHO2-}\\
        \textrm{C: 4 valence electrons/atom × 1 atom} \hspace{6px}= \phantom{1}4\\
        \textrm{H: 1 valence electron/atom × 1 atom} \hspace{12px}= \phantom{1}1\\
        \textrm{O: 6 valence electrons/atom × 2 atoms = 12}\\
        \underline{+\hspace{100px}\textrm{1 additional electron} \hspace{9px}= \phantom{1}1}\\
        \hspace{264px}\textrm{= 18 valence electrons}\)

      • For a positive ion, such as NO+, we add the number of valence electrons on the atoms in the ion and then subtract the number of positive charges on the ion (one electron is lost for each single positive charge) from the total number of valence electrons:

        \(\ce{NO+}\\
        \textrm{N: 5 valence electrons/atom × 1 atom} = \phantom{−}5\\
        \textrm{O: 6 valence electron/atom × 1 atom}\hspace{5px} = \phantom{−}6\\
        \underline{\textrm{+ −1 electron (positive charge)} \hspace{44px}= −1}\\
        \hspace{260px}\textrm{= 10 valence electrons}\)

      • Since OF2 is a neutral molecule, we simply add the number of valence electrons:

        \(\phantom{+ }\ce{OF2}\\
        \phantom{+ }\textrm{O: 6 valence electrons/atom × 1 atom} \hspace{10px}= 6\\
        \underline{\textrm{+ F: 7 valence electrons/atom × 2 atoms} = 14}\\
        \hspace{280px}\textrm{= 20 valence electrons}\)

    2. Draw a skeleton structure of the molecule or ion, arranging the atoms around a central atom and connecting each atom to the central atom with a single (one electron pair) bond. (Note that we denote ions with brackets around the structure, indicating the charge outside the brackets:)

    10.4: Lewis Structures of Molecular Compounds (4)

    1. When several arrangements of atoms are possible, as for \(\ce{CHO2-}\), we must use experimental evidence to choose the correct one. In general, the less electronegative elements are more likely to be central atoms. In \(\ce{CHO2-}\), the less electronegative carbon atom occupies the central position with the oxygen and hydrogen atoms surrounding it. Other examples include P in POCl3, S in SO2, and Cl in \(\ce{ClO4-}\). An exception is that hydrogen is almost never a central atom. As the most electronegative element, fluorine also cannot be a central atom.
    2. Distribute the remaining electrons as lone pairs on the terminal atoms (except hydrogen) to complete their valence shells with an octet of electrons.
      • There are no remaining electrons on SiH4, so it is unchanged:

    10.4: Lewis Structures of Molecular Compounds (5)

    1. Place all remaining electrons on the central atom.
      • For SiH4, \(\ce{CHO2-}\), and NO+, there are no remaining electrons; we already placed all of the electrons determined in Step 1.
      • For OF2, we had 16 electrons remaining in Step 3, and we placed 12, leaving 4 to be placed on the central atom:

    10.4: Lewis Structures of Molecular Compounds (6)

    1. Rearrange the electrons of the outer atoms to make multiple bonds with the central atom in order to obtain octets wherever possible.
      • SiH4: Si already has an octet, so nothing needs to be done.
      • \(\ce{CHO2-}\): We have distributed the valence electrons as lone pairs on the oxygen atoms, but the carbon atom lacks an octet:

    10.4: Lewis Structures of Molecular Compounds (7)

    • NO+: For this ion, we added eight outer electrons, but neither atom has an octet. We cannot add any more electrons since we have already used the total that we found in Step 1, so we must move electrons to form a multiple bond:

    10.4: Lewis Structures of Molecular Compounds (8)

    • This still does not produce an octet, so we must move another pair, forming a triple bond:

    10.4: Lewis Structures of Molecular Compounds (9)

    • In OF2, each atom has an octet as drawn, so nothing changes.
    Example \(\PageIndex{1}\): Writing Lewis Structures

    NASA’s Cassini-Huygens mission detected a large cloud of toxic hydrogen cyanide (HCN) on Titan, one of Saturn’s moons. Titan also contains ethane (H3CCH3), acetylene (HCCH), and ammonia (NH3). What are the Lewis structures of these molecules?

    Solution

    Calculate the number of valence electrons.

    • HCN: (1 × 1) + (4 × 1) + (5 × 1) = 10
    • H3CCH3: (1 × 3) + (2 × 4) + (1 × 3) = 14
    • HCCH: (1 × 1) + (2 × 4) + (1 × 1) = 10
    • NH3: (5 × 1) + (3 × 1) = 8

    Draw a skeleton and connect the atoms with single bonds. Remember that H is never a central atom:

    10.4: Lewis Structures of Molecular Compounds (10)

    Where needed, distribute electrons to the terminal atoms:

    10.4: Lewis Structures of Molecular Compounds (11)

    • HCN: six electrons placed on N
    • H3CCH3: no electrons remain
    • HCCH: no terminal atoms capable of accepting electrons
    • NH3: no terminal atoms capable of accepting electrons

    Where needed, place remaining electrons on the central atom:

    10.4: Lewis Structures of Molecular Compounds (12)

    • HCN: no electrons remain
    • H3CCH3: no electrons remain
    • HCCH: four electrons placed on carbon
    • NH3: two electrons placed on nitrogen

    Where needed, rearrange electrons to form multiple bonds in order to obtain an octet on each atom:

    • HCN: form two more C–N bonds
    • H3CCH3: all atoms have the correct number of electrons
    • HCCH: form a triple bond between the two carbon atoms
    • NH3: all atoms have the correct number of electrons

    10.4: Lewis Structures of Molecular Compounds (13)

    Exercise \(\PageIndex{1}\)

    Both carbon monoxide, CO, and carbon dioxide, CO2, are products of the combustion of fossil fuels. Both of these gases also cause problems: CO is toxic and CO2 has been implicated in global climate change. What are the Lewis structures of these two molecules?

    Answer

    10.4: Lewis Structures of Molecular Compounds (14)

    Fullerene Chemistry

    Carbon soot has been known to man since prehistoric times, but it was not until fairly recently that the molecular structure of the main component of soot was discovered. In 1996, the Nobel Prize in Chemistry was awarded to Richard Smalley, Robert Curl, and Harold Kroto for their work in discovering a new form of carbon, the C60 buckminsterfullerene molecule. An entire class of compounds, including spheres and tubes of various shapes, were discovered based on C60. This type of molecule, called a fullerene, consists of a complex network of single- and double-bonded carbon atoms arranged in such a way that each carbon atom obtains a full octet of electrons. Because of their size and shape, fullerenes can encapsulate other molecules, so they have shown potential in various applications from hydrogen storage to targeted drug delivery systems. They also possess unique electronic and optical properties that have been put to good use in solar powered devices and chemical sensors.

    Summary

    Valence electronic structures can be visualized by drawing Lewis symbols (for atoms and monatomic ions) and Lewis structures (for molecules and polyatomic ions). Lone pairs, unpaired electrons, and single, double, or triple bonds are used to indicate where the valence electrons are located around each atom in a Lewis structure. Most structures—especially those containing second row elements—obey the octet rule, in which every atom (except H) is surrounded by eight electrons. Exceptions to the octet rule occur for odd-electron molecules (free radicals), electron-deficient molecules, and hypervalent molecules.

    Glossary

    double bond
    covalent bond in which two pairs of electrons are shared between two atoms
    free radical
    molecule that contains an odd number of electrons
    hypervalent molecule
    molecule containing at least one main group element that has more than eight electrons in its valence shell
    Lewis structure
    diagram showing lone pairs and bonding pairs of electrons in a molecule or an ion
    Lewis symbol
    symbol for an element or monatomic ion that uses a dot to represent each valence electron in the element or ion
    lone pair
    two (a pair of) valence electrons that are not used to form a covalent bond
    octet rule
    guideline that states main group atoms will form structures in which eight valence electrons interact with each nucleus, counting bonding electrons as interacting with both atoms connected by the bond
    single bond
    bond in which a single pair of electrons is shared between two atoms
    triple bond
    bond in which three pairs of electrons are shared between two atoms
    10.4: Lewis Structures of Molecular Compounds (2024)

    FAQs

    What is the Lewis structure for molecular compounds? ›

    A Lewis Structure is a very simplified representation of the valence shell electrons in a molecule. It is used to show how the electrons are arranged around individual atoms in a molecule. Electrons are shown as "dots" or for bonding electrons as a line between the two atoms.

    How to check if an octet is complete? ›

    The octet rule states that each atom should have 8 valence electrons to be satisfied. First, determine the number of electrons from lone pairs and bonds to the atom. Each lone pair donates two valence electrons to the atom and each bond, represented by a line, gives two valence electrons to the atom.

    How do you answer Lewis structure? ›

    Step 1: Determine the total number of valence electrons. Step 2: Write the skeleton structure of the molecule. Step 3: Use two valence electrons to form each bond in the skeleton structure. Step 4: Try to satisfy the octets of the atoms by distributing the remaining valence electrons as nonbonding electrons.

    What is the molecular bond of ch4? ›

    Methane, CH4, is a covalent compound with exactly 5 atoms that are linked by covalent bonds. We draw this covalent bonding as a Lewis structure (see diagram). The lines, or sticks, as we say, represent the covalent bonds. There are four bonds from a central carbon (C) linking or bonding it to four hydrogen atoms (H).

    How many valence electrons does ch4 have? ›

    For CH4 you have a total of 8 total valence electrons.

    Which Lewis structure is correct? ›

    Just to clarify, a way of checking if your lewis structure is correct is by adding up the formal charges to get the total charge, and if the total charge matches the charge of whatever molecule or ion you are drawing, then you know that you are on the right track.

    What are examples of molecular compounds? ›

    Molecular compounds are chemical compounds that take the form of discrete molecules. Examples include such familiar substances as water (H2O) and carbon dioxide (CO2) (Figure 3.1. 1). These compounds are very different from ionic compounds like sodium chloride (NaCl).

    What is Lewis' octet rule? ›

    Lewis formulated the "octet rule" in his cubical atom theory. The octet rule refers to the tendency of atoms to prefer to have eight electrons in the valence shell. When atoms have fewer than eight electrons, they tend to react and form more stable compounds. Atoms will react to get in the most stable state possible.

    What breaks the octet rule? ›

    The Octet Rule is violated in these three scenarios: When there are an odd number of valence electrons. When there are too few valence electrons. When there are too many valence electrons.

    What are the three rules for Lewis structure? ›

    4.10: Rules for Writing Lewis Formulas
    • Determine the total number of valence electrons in the molecule or ion.
    • Arrange the atoms to show specific connections.
    • Place a bonding pair of electrons between each pair of adjacent atoms to give a single bond.
    Sep 23, 2021

    What is a Lewis structure example? ›

    Lewis Structures

    For example, when two chlorine atoms form a chlorine molecule, they share one pair of electrons: The Lewis structure indicates that each Cl atom has three pairs of electrons that are not used in bonding (called lone pairs) and one shared pair of electrons (written between the atoms).

    What can a Lewis structure tell you? ›

    Lewis structures (also known as Lewis dot structures or electron dot structures) are diagrams that represent the valence electrons of atoms within a molecule. These Lewis symbols and Lewis structures help visualize the valence electrons of atoms and molecules, whether they exist as lone pairs or within bonds.

    What is the structure of CH4 element? ›

    Methane (US: METH-ayn, UK: MEE-thayn) is a chemical compound with the chemical formula CH4 (one carbon atom bonded to four hydrogen atoms). It is a group-14 hydride, the simplest alkane, and the main constituent of natural gas.

    Why the structure of CH4 is tetrahedral? ›

    In CH4 molecule, carbon atom is sp3- hybridised not dsp2 or sp2d since d- orbitals are not present in carbon atom. The bond angle in CH4 molecule is 109°28'. It suggests that CH4 molecule is tetrahedral.

    Is the structure of CH4 polar or nonpolar? ›

    Methane is non-polar molecule because of its symmetrical tetrahedral structure.

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